Tuesday 15 March 2016

INTEGRATION AND CONTROL METABOLISM: 2013/2014 MIDTRIM QUESTIONS AND ANSWERS



Q1.
The three major junctions of intermediary metabolism are glucose-6-phosphate, acetyl Co-A and pyruvate.
1.      Glucose 6-phosphate
Glucose entering a cell is rapidly phosphorylated to glucose 6-phosphate and is subsequently stored as glycogen, degraded to pyruvate, or converted into ribose 5-phosphate. Glycogen is formed when glucose 6-phosphate and ATP are abundant in the cell. In contrast, glucose 6-phosphate flows into the glycolytic pathway when ATP or acetyl Co-A for biosynthesis are required. The third fate of glucose 6-phosphate is to flow through the pentose phosphate pathway, which provides NADPH for reductive biosynthesis and ribose 5-phosphate for the synthesis of nucleotides. Glucose 6-phosphate can be formed by the mobilization of glycogen or it can be synthesized from pyruvate and glucogenic amino acids by the gluconeogenic pathway.

2.      Pyruvate
This three-carbon α-ketoacid is another major metabolic junction. Pyruvate is derived primarily from glucose 6-phosphate, alanine, and lactate. Pyruvate can be reduced to lactate by lactate dehydrogenase to regenerate NAD+. The lactate formed in active tissue is subsequently oxidized back to pyruvate, in other tissues. Another readily reversible reaction in the cytosol is the transamination of pyruvate, and α-ketoacid, to alanine, the corresponding amino acid. Conversely, several amino acids can be converted into pyruvate. Thus, transamination is a major link between amino acid and carbohydrate metabolism. A third fate of pyruvate is its carboxylation to oxaloacetate inside mitochondria, the first step in gluconeogenesis. The carboxylation of pyruvate is also important for replenishing intermediates of the citric acid cycle. A fourth fate of pyruvate is its oxidative decarboxylation to acetyl CoA. This irreversible reaction inside mitochondria is a decisive reaction in metabolism: it commits the carbon atoms of carbohydrates and amino acids to oxidation by the citric acid cycle or to the synthesis of lipids. Pyruvate is rapidly converted into acetyl CoA only if ATP is needed or if two-carbon fragments are required for the synthesis of lipids.

3.      Acetyl CoA
The major sources of this activated two-carbon unit are the oxidative decarboxylation of pyruvate and the β-oxidation of fatty acids. Acetyl CoA is also derived from ketogenic amino acids. The acetyl unit can be completely oxidized to CO2 by the citric acid cycle. Alternatively, 3-hydroxy-3-methylglutaryl CoA can be formed from three molecules of acetyl CoA. This six-carbon unit is a precursor of cholesterol and of ketone bodies.  A third major fate of acetyl CoA is its export to the cytosol in the form of citrate for the synthesis of fatty acids.



Q2.
Discuss the key regulatory steps in glycolysis and the Tricarboxylic Acid Cycle
Answer
First regulatory step the action of hexokinase or glucokinase
This enzyme is strongly inhibited by the product of its reaction, glucose-6-phosphate, thus preventing the unnecessary utilization of ATP which could be used for other metabolic process. But glucokinase the isozyme of hexokinase found in the liver and pancreas has a higher Km and is not subject to feedback inhibition by glucose-6-phosphate. The lower Km of hexokinase is important for tissues such as those of the brain because it allows glucose to be phosphorylated even at concentrations lower than the normal physiological blood/tissue levels. Glucokinase is also subject to induction/suppression of synthesis under hormonal control. The presence of insulin increases the amount of glucokinase through the promotion of the transcription of the glucokinase gene and vice versa when glucagon is predominant.

Second regulatory step the action of phosphofructokinase-1(PFK-1)
This is the most important regulatory step in the glycolytic pathway because it’s the first committed step in this pathway. This enzyme is allostericaly inhibited by citrate, ATP and H+ (also called negative effectors). Citrate an intermediate of the TCA cycle inhibits PFK-1 when its cytosolic concentrations are high. ATP is both a substrate and in most cases an allosteric inhibitor of this enzyme; at high concentrations it causes a decrease in the affinity of this enzyme for fructose-6-phosphate thus increasing the Km of the enzyme. H+ is a glycolytic end product (lactic acid), which inhibits PFK-1 and shuts off the glycolysis to prevent lacto-acidosis. AMP, F-2-BP and Pi are positive effectors PFK-1, a decrease in the ATP concentration causes elevated levels of AMP. This makes it an excellent signal of the energy status of the cell and act as a positive allosteric effector of PFK-1 thus decreasing its Km. Fructose-2, 6-bisphosphate (F-2-BP) is formed from F-2-B by the action of phosphofructokinase-2 which is stimulated by Pi and inhibited by citrate. In the presence of F-2-BP, PFK-1 is activated increasing its Km.

Third regulatory step pyruvate kinase (PK) activity
PK is drastically inhibited by high concentrations of ATP and reduces the apparent affinity of PK for PEP. PK is also activated by F-1,6-P, thus the activation of PFK-1 causes a subsequent activation of PK. Acetyl Co-A acts as an allosteric inhibitor of PK, this occurs when there is excessive production of acetyl Co-A. A high glucagon/insulin ratio also causes a repression of the synthesis of PK leading to reduced glycolysis and stimulation of gluconeogenesis (coarse control)
Tricarboxylic Acid cycle (TCA cycle)
The passage of carbons of pyruvate into and through the TCA cycle is under control at two levels.
Ø  The conversion of pyruvate to acetyl Co-A for entry into the cycle
Ø  Regulation by key enzyme in the TCA under the allosteric influence of cofactors and intermediates
Pyruvate dehydrogenase complex is regulated by fine control mechanism
Allosteric control
The transacetylase component (E2) is inhibited by acetyl- CoA and activated by CoASH
The dihydrolipoamide dehydrogenase component (E3) is inhibited by NADH and activated by NAD+
ATP is an allosteric inhibitor of the complex whiles AMP is an activator of it.

Covalent modification
NADH and acetyl-CoA do not only inhibit the dephospho-form (active) of the PDH complex but also activate PDH kinase leading to the phosphorylation and the inactivation of the complex
Free CoASH and NAD+ inhibit the PDH kinase, thus activating the PDH complex
Pyruvate is a potent inhibitor of the PDH kinase and therefore in the presence of elevated tissue pyruvate levels, the kinase will be inhibited and the PDH complex maximally activated.

Regulation of the TCA cycle it self
The regulation is three exergonic steps in the cycle catalysed by (i) citrate synthase, (ii) isocitrate dehydrogenase and (iii) α-ketoglutarate dehydrogenase
(i)                 The availability of substrate for this enzyme  (acetyl Co-A and oxaloacetate) depends on the metabolic state of the cell and thus may limit the rate of citrate formation
(ii)               And (iii)
NADH a product of dehydrogenation reactions accumulates under some conditions and at high NADH/NAD+ ratio both are   severely inhibited
 Product accumulation: the accumulation of the products of all the three limiting steps inhibits feedback inhibit their respective enzymes
Respiratory control: anything that affects the supply of O2, ADP and reducing equivalent would shut down the cycle which is sometimes referred to as coarse control.


Q3
Discuss the control and regulation of glycogenolysis: Indicate key enzymes and secondary messengers that are involved in this.
ANSWER
Glycogenolysis is the catabolism of glycogen and is catalysed by the enzyme glycogen phosphorylase. It is a regulatory enzyme and hence subject fine control by allosteric effectors and covalent modification and it catalyses the first step in this pathway. The enzyme glycogen phosphorylase is allostericaly activated by AMP and allostericaly inhibited by glucose and ATP.
Glycogen phosphorylase is also subject to covalent modification, the enzyme exist in two forms a (the active form) and b (the inactive form). These forms of the enzyme undergo interconvertions by the actions of phosphorylase kinase and phosphoprotein phosphatase as described below

 
Q4
Distinguish between non-equilibrium and near equilibrium reactions in metabolic pathways and explain the need for regulation in metabolic pathways.
ANSWER
In near equilibrium reactions the rate of the forward reactions equal the rate of the backward reaction and there is no net flux in either direction, such reactions are readily reversible but in non-equilibrium reactions are those reactions that occurs in only one direction (rate of the forward and the reverse reactions are not equal) as such there is a net flux in one direction, such reactions are usually irreversible.
Metabolic pathways need to be controlled and regulated for various reasons which include;
Ø  The fact that organisms feed intermittently, most organisms are not continually feeding even though the requirement for cell energy and building material remains fairly constant. As such there should be a mechanism to ensure that excess fuel molecules are stored after meal released when required. Thus the rate of utilization of fuel molecules is dependent on their supply to the cell. For example an organism’s rate of utilization of glucose depends on   several factors which include the release of insulin/glucagon from the pancreas.
Ø  The need to maintain homeostasis, for organisms to survive they need to maintain a constant internal environment. For example glucose needs to be maintained at 5mM. The consumption of a carbohydrate rich diet may increase the blood glucose to 12mM; under these circumstances every cell increases their rate of glucose utilization to bring the level to normal. Conversely when the level of glucose falls, it utilization is minimized to conserve it for the brain, also the liver sets into motion processes that begins the synthesis of glucose from non-carbohydrate sources. Thus the ability to maintain glucose homeostasis depends on the mechanisms that alter the rate of glucose metabolism depending on metabolic circumstances.
Ø  The need to satisfy the peculiar demands of various tissues and organs, the brain, liver and adipose tissue differ not only in their functions but also in their energy requirements and preferences. For example the brain utilizes glucose as the major energy source while resting muscles prefer fatty acids. Since the composition of food ingested may vary, it may be necessary to alter the relative amounts of the various fuel molecules in order to satisfy the demands of every type of cell. This is the responsibility of the liver and involves regulation of the rates of the various metabolic pathways in the hepatocytes.  
Ø  Variations in levels of physical activity, the consumption of energy is proportional to the intensity of physical activity. Then since organisms do not undergo a constant level of physical activity the consumption of muscles varies. Hence mechanisms involved in the control of energy metabolism are closely linked to the level of physical activity.
Q5
Enumerate four central features of metabolic pathways and explain them.
ANSWER
1.      Coordination and regulation of biosynthetic pathway; most of these pathways are not independent and thus they need to be regulated and coordinated to ensure a certain degree of order in the system. For example the biosynthesis of glucose from acetyl Co-A can only occur place when there is the need for it but there is no need mobilizing resources to make glucose when there are other glucose sources such as glycogen is available. The glucose synthesis can only take place when tissues such as the brain which uses glucose as it sole source of energy is glucose is in the need of it.  Hence all metabolic pathways are regulated and coordinated to ensure efficient utilization of resources.

2.       ATP is the universal currency of energy. The high phosphoryl transfer potential of ATP enables it to serve as the energy source in muscle contraction, active transport, signal amplification, and biosynthesis. The hydrolysis of an ATP molecule changes the equilibrium ratio of products to reactants in a coupled reaction by a factor of about 108. Hence, a thermodynamically unfavourable reaction sequence can be made highly favourable by coupling it to the hydrolysis of a sufficient number of ATP molecules.

3.       ATP is generated by the oxidation of fuel molecules such as glucose, fatty acids, and amino acids. The common intermediate in most of these oxidations is acetyl CoA. The carbon atoms of the acetyl unit are completely oxidized to CO2 by the citric acid cycle with the concomitant formation of NADH and FADH2. These electron carriers then transfer their high potential electrons to the respiratory chain. The subsequent flow of electrons to O2 leads to the pumping of protons across the inner mitochondrial membrane. This proton gradient is then used to synthesize ATP. Glycolysis also generates ATP, but the amount formed is much smaller than that in oxidative phosphorylation. The oxidation of glucose to pyruvate yields only 2 molecules of ATP, whereas the complete oxidation of glucose to CO2 yields 30 molecules of ATP.

4.      NADPH is the major electron donor in reductive biosynthesis. In most biosynthesis, the products are more reduced than the precursors, and so reductive power is needed as well as ATP. The high-potential electrons required to drive these reactions are usually provided by NADPH. The pentose phosphate pathway supplies much of the required NADPH.

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